To divide a line segment AB into three equal parts we have to find two points P and Q such that AP = PQ= QB
Let AP = PQ = QB = k
Then AP = k and PB = PQ + QB = k + k=2k
That means P divides the line segment in the ratio k : 2k = 1 : 2
The coordinates of can be found by using the section formula for coordinates and using the ration 1:2
Similarly, AQ = AP + PQ = k + k = 2k and QB = k
Find the coordinates of the points of trisection of the line segment joining (4, -1) and (-2, -3). | |||
Right Option : A | |||
View Explanation |
Find the coordinates of the points of trisection of the line segment joining (4, -1) and (1, -3). | |||
Right Option : B | |||
View Explanation |
In the given figure P(5,-3) and Q(3,y) are the points of trisection of the line segment joining A(7,-2) and B(1,-5). Then, y equals : | |||
Right Option : C | |||
View Explanation |
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